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Given the value of Rydberg constant is 107m–1, the wave number of the last line of the Balmer series in hydrogen spectrum will be :-
(a)0.025 × 104 m–1
(b)0.5 × 107 m–1
(c)0.25 × 107 m–1
(d)2.5 × 107 m–1

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Important Questions on Atomic Physics
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If an electron in a hydrogen atom jumps from the orbit to the orbit, it emits a photon of wavelength $\lambda$. When it jumps from the orbit to the orbit, the corresponding wavelength of the photon will be

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The ratio of wavelength of the last line of Balmer series and the last line Lyman series is:

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In an H-like atom when electron transits from energy state n=5 to n=2, a photon of wavelength 434 nm is emitted. What will be the wavelength of photon emitted when the transition occurs from energy state n=4 to n=2?

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The ratio of kinetic energy to the total energy of an electron in a Bohr orbit of the hydrogen atom, is :-

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For a hydrogen like atom, wavelength of third transition of Balmer series is = 108.5 nm. The binding energy of atom is

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A X-ray tube operates at potential 15 kV. Find the minimum wavelength of X-ray.

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Wavelength of photon in H-atom is 434 nm in transition from n = 5 to n= 2. Wavelength of photon for same transition in He+ atoms is :-

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What is the velocity of electron in second orbit of He+ ion
