HCF of co-prime numbers 4 and 15 was found as follows by factorization: 4 = 2 × 2 and 15 = 3 × 5 . Since there is no common prime factor, HCF of 4 and 15 is 0 . Is the answer correct? If not, what is the correct HCF?

Here, 'HCF of 4 and 15 is 0 ' is wrong. This is because the given factorizations 4 = 2 × 2 and 15 = 3 × 5 is wrong. The correct factorizations are 4 = 1 × 2 × 2 and 15 = 1 × 3 × 5 . It is true that there is no common prime factors between the factors of 4 and 15 , but, the factor 1 (although 1 is not a prime number) is available as common factors in them. For a factor to be HCF, it is not necessary that it has to be a prime factor, HCF may be the non-prime number also. Therefore, the correct HCF of 4 and 15 is 1 .

HCF of co-prime numbers 4 and 15 was found as follows by factorization: 4 = 2 × 2 and 15 = 3 × 5 . Since there is no common prime factor, HCF of 4 and 15 is 0 . Is the answer correct? If not, what is the correct HCF?

Here, 'HCF of 4 and 15 is 0 ' is wrong. This is because the given factorizations 4 = 2 × 2 and 15 = 3 × 5 is wrong. The correct factorizations are 4 = 1 × 2 × 2 and 15 = 1 × 3 × 5 . It is true that there is no common prime factors between the factors of 4 and 15 , but, the factor 1 (although 1 is not a prime number) is available as common factors in them. For a factor to be HCF, it is not necessary that it has to be a prime factor, HCF may be the non-prime number also. Therefore, the correct HCF of 4 and 15 is 1 .