Heat of dissociation of acetic acid is$0.30 \mathrm{kcal} {\mathrm{mol}}^{-1}$, and the heat of neutralization of $\mathrm{Ca}{\left(\mathrm{OH}\right)}_2$ is $13.7 \mathrm{k} \mathrm{cal} {\mathrm{mol}}^{-1}$ . Hence, enthalpy change when$1 \mathrm{mole}$ of$\mathrm{Ca}(\mathrm{OH}{)}_2$ is completely neutralized by acetic acid would be

Oxidising power of chlorine in aqueous solution can be determined by the parameters indicated below:

$\frac{1}{2}{\mathrm{Cl}}_2\left(\mathrm{g}\right)\stackrel{\frac{1}{2}{∆}_{\mathrm{disso}}{\mathrm{H}}^{\odot }}{\to }\mathrm{Cl}\left(\mathrm{g}\right)\stackrel{{∆}_{\mathrm{eg}}{\mathrm{H}}^{\odot }}{\to }{\mathrm{Cl}}^{-}\left(\mathrm{g}\right)\stackrel{{∆}_{\mathrm{hyd}}{\mathrm{H}}^{\odot }}{\to }{\mathrm{Cl}}^{-}\left(\mathrm{aq}\right)$

The energy involved in the conversion of $\frac{1}{2}{\mathrm{Cl}}_2\left(\mathrm{g}\right) \mathrm{to} {\mathrm{Cl}}^{-}\left(\mathrm{aq}\right)$ (using the data, ${∆}_{\mathrm{disso}}{{\mathrm{H}}^{\odot }}_{{\mathrm{Cl}}_2}=240\mathrm{KJ} {\mathrm{mol}}^{-1}$ ,${∆}_{\mathrm{eg}}\mathrm{H}=-349\mathrm{KJ} {\mathrm{mol}}^{-1}$ ${∆}_{\mathrm{hyd}}{\mathrm{H}}_{\mathrm{Cl}}^{\odot }-=-381\mathrm{KJ} {\mathrm{mol}}^{-1}$ ) will be