
Horizontal force is applied on a uniform circular disc of mass and radius which can rotate in vertical plane about an axes passing through as shown. What is the acceleration of bottom most point on the disc at this instant?




Important Questions on System of Particles and Rotational Motion
Consider the shown diagram. A fixed vertical smooth rod is kept in front of a uniform disc of mass and radius which is rolling without slipping on a rough horizontal surface. Velocity of centre of disc is . A rod of length is connected with disc at , (point is at a vertical distance of from centre of disc) by pin joint and other end of rod can freely slide over smooth vertical rod . At this instant rod makes an angle with rod as shown. Find the angular velocity of rod at this instant.

A uniform circular disc of mass and radius is fixed to vertical axis with the help of a rod of length as shown. The disc rolls on a horizontal surface and is free to rotate about its centre. If there is no slipping at the point of contact of disc and horizontal surface then kinetic energy of the disc will be (given )

A uniform circular disc of mass and radius is having a point mass at its circumference is performing rolling without slipping over a rough horizontal surface as shown. Acceleration of point is towards right. If is the normal reaction on disc by the horizontal surface at this instant then

A rod of mass and length is pivoted at the bottommost point and can freely rotate about the point . The rod is disturbed from the vertical position so that it starts rotating about . When it makes an angle with the vertical


A uniform rod of mass and length is placed over a smooth horizontal surface. A particle of mass moving horizontally with velocity hits the rod at one end perpendicularly as shown in figure and comes to rest. Then


Statement-I: If there is no external torque on a body about its centre of mass, then the velocity of the centre of mass remains constant.
Statement-2: The linear momentum of an isolated system remains constant.
