How many digits will be there to the right of the decimal point in the product of $95.75$ and $0.02554$?

$5.36\times 3.6=?$

Simplify : $\frac{9+2\times 3.3}{0.003}$

(A) 12,100 

(B) 5,200 

(C) 520 

(D) 1,210 

$\frac{1}{25}$ of the students who registered did not appear for the examination, $\frac{11}{20}$ of those who appeared passed. If the number of registered students is $2000$, the number who passed is:

Simplify: 25.67 + 9.208 + 152.1 + 63.2 

(A) 248.718 

(B) 250.718 

(C) 248.178 

(D) 250.178