How many geometrical isomers are possible for the given compound?

${\mathrm{CH}}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}={\mathrm{CH}}_2$

How many geometrical isomers are possible for the given compound?

Total number of geometrical isomers in the given compound is:

Total number of geometrical isomers in the given compound is:

Number of Geometrical isomers for following compound is:

$$\begin{gathered} {\mathrm{CH}}_3-\mathrm{CH}-\mathrm{CH}-\mathrm{CH}-{\mathrm{CH}}_3 \\ \overline{) \overline{) \overline{)}}} \\ \mathrm{Br} \mathrm{Br} \mathrm{Br} \end{gathered}$$

Total number of stereoisomers in above compound is:

$$\begin{gathered} {\mathrm{CH}}_3-\mathrm{CH}-\mathrm{CH}-\mathrm{CH}-{\mathrm{CH}}_3 \\ \overline{) \overline{) \overline{)}}} \\ \mathrm{Cl} \mathrm{Br} \mathrm{OH} \end{gathered}$$

Total number of stereoisomers in above compound is: