Draw any line segment A B . Without measuring A B ¯ construct a copy of A B ¯ .

Steps : Draw a line segment AB of unknown length. Fix the compass' pointer on the point A and pencil pointer on B gives you the length of AB. Now draw a straight line using a ruler, let's say line o. Mark a point x and fix the compass pointer on x without changing the settings and cut an arc on line o. Name the point as y. xy is of same length as AB

Construct any line segment PQ . Construct AB ¯ such that AB ¯ = 3 PQ ¯ .

Following steps: Draw any line segments PQ using scale. Draw another reference line l and take any point A on the line. Measure the length PQ using compass. A as center and PQ measure as radius draw an arc on reference line like AX = PQ again X as center draw another arc on same direction on the same line like XY = PQ similarly by the same draw an arc like YB = PQ . AB ¯ = 3 PQ ¯ as shown in the figure. Hence, AB is the required line like AB = 3 PQ as shown below.

Draw an angle of 120 ° with vertex O . Take point A on one of its arms and B on another arm such that OA ¯ = OB ¯ . Draw perpendicular bisectors of OA ¯ and OB ¯ . Let them meet at P . Are PA ¯ and PB ¯ equal in length ?

We can construct an angle bisector by following the steps below. Step 1: Draw an angle of 120 ° with vertex as O . Step 2: Take O as centre make two arcs on both rays of this angle. Mark these points as A and B. Step 3: By taking O and A as centres and with a radius, more than half of O A , draw two arcs on both the sides of O A and mark the points as C and D where the arcs intersect each other. Step 4: Join C D to construct a perpendicular bisector of O A . Step 5: By taking O and B as centres and with a radius of more than half of O B , draw two arcs on both sides of O B and mark the points as E and F where the arcs intersect each other. Step 6: Join E F to construct a perpendicular bisector of O B . The perpendicular bisectors C D and E F intersect each other at point P . On measuring we see that, P A = P B .