How will you convert:

Benzene into aniline.

How will you convert:

Benzene into  $\mathrm{N},\mathrm{N}$-dimethylaniline.

Arrange the following in increasing order of their basic strength:

 ${\mathrm{C}}_2{\mathrm{H}}_5{\mathrm{NH}}_2, {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NH}}_2, {\mathrm{NH}}_3, {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2{\mathrm{NH}}_2$ and ${\left({\mathrm{C}}_2{\mathrm{H}}_5\right)}_2\mathrm{NH}$

Arrange the following in increasing order of their basic strength:

 ${\mathrm{C}}_2{\mathrm{H}}_5{\mathrm{NH}}_2, {\left({\mathrm{C}}_2{\mathrm{H}}_5\right)}_2\mathrm{NH}, {\left({\mathrm{C}}_2{\mathrm{H}}_5\right)}_3\mathrm{N}, {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NH}}_2$.

Complete the following acid-base reaction and name the product:

${\mathrm{C}\mathrm{H}}_3{\mathrm{C}\mathrm{H}}_2{\mathrm{C}\mathrm{H}}_2{\mathrm{N}\mathrm{H}}_2+\mathrm{H}\mathrm{C}\mathrm{l}⟶$

Complete the following acid-base reaction and name the product:

${\left({\mathrm{C}}_2{\mathrm{H}}_5\right)}_3\mathrm{N}+\mathrm{H}\mathrm{C}\mathrm{l}\to$