Hydrogen ( 1 H 1 ), Deuterium ( 1 H 2 ), singly ionised Helium ( 2 He 4 ) + and doubly ionised lithium ( 3 Li 6 ) ++ all have one electron around the nucleus. Consider an electron transition from n = 2 to n = 1 . If the wave lengths of emitted radiation are λ 1 , λ 2 , λ 3 and λ 4 respectively then approximately which one of the following is correct ?

4 λ 1 = 2 λ 2 = 2 λ 3 = λ 4

λ 1 = 2 λ 2 = 3 λ 3 = 4 λ 4

HARD

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Hydrogen alpha emission line emitted from a galaxy, corresponding to Balmer series transition from $n = 3$ to $n = 2$ , is found to be Doppler shifted to $652.4 nm$ . It can be concluded that the galaxy is

$R = 1.097 \times 10^{7} m^{- 1}$

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Important Questions on Atomic Physics

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

In Balmer series, wavelength of first line is

λ_{1}

and in Brackett series wavelength of first line is

λ_{2}

then

\frac{λ_{1}}{λ_{2}}

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

Given the value of Rydberg constant is

10^{7} m^{- 1}

, the wave number of the last line of the Balmer series in hydrogen spectrum will be:

MEDIUM

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

Taking the wavelength of first Balmer line in hydrogen spectrum

(n = 3

n = 2)

660 n m

, the wavelength of the

2^{n d}

Balmer line

(n = 4

n = 2)

will be :

MEDIUM

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

The shortest wavelength of Paschen series in hydrogen spectrum is

8182 \overset{\circ}{A}

. The first member of the Paschen series is nearly

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

The frequency for a series limit of Balmer and Paschen series respectively are

f_{1}

and

f_{3}

. If the frequency of the first line of Balmer series is

f_{2}

then the relation between

f_{1}, f_{2}

and

f_{3}

MEDIUM

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

The energy required to ionise a hydrogen like ion in its ground state is

9

Rydbergs. What is the wavelength of the radiation emitted when the electron in this ion jumps from the second excited state to the ground state?

MEDIUM

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

The first member of the Balmer series of hydrogen atom has a wavelength of

6561 \overset{\circ}{A}

. The wavelength of the second member of the Balmer series (in nm) is_____________

HARD

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

R

is the Rydberg constant in

{cm}^{- 1}

, then hydrogen atom does not emit any radiation of wavelength in the range of

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

The ratio of wavelengths of the last line of the Balmer series and the last line of the Lyman series is_____.

MEDIUM

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

If the series limit frequency of the Lyman series is

V_{L},

then the series limit frequency of the Pfund series is:

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

The series corresponding to lowest wavelength transition in

H

- atom.

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is:

HARD

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

In hydrogen spectrum,

L_{α}

line arises due to transition of electron from the orbit

n = 3

to the orbit

n = 2

. In the spectrum of singly ionized helium, there is a line having the same wavelength as that of the

L_{α}

line of hydrogen. This is due to the transition of the electron from the orbit ______ to ________

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

When the electron in hydrogen atom jumps from fourth Bohr orbit to second Bohr orbit, one gets the

MEDIUM

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

Hydrogen atom in its ground state is excited by a monochromatic light of energy

13.06 eV

. The longest wavelength among the spectral lines is (Ionization energy of hydrogen atom is

13.6 eV

)

HARD

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

The Hitomi satellite recently observed the Lyman alpha emission line (

n = 2

n = 1

) of hydrogen-like iron ion (atomic number of iron is

26

) from the Perseus galaxy cluster. The wavelength of the line is closest to

HARD

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

In a muonic atom, a muon of mass of

200

times of that of electron and same charge is bound to the proton. The wavelengths of its Balmer series are in the range of

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

An electron from various excited states of hydrogen atom emit radiation to come to the ground state. Let

λ_{n}, λ_{g}

be the de Broglie wavelength of the electron in the

n^{t h}

state and the ground state respectively. Let

\land_{n}

be the wavelength of the emitted photon in the transition from the

n^{t h}

state to the ground state. For large n, (A, B are constants)

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

In Balmer series for hydrogen atom, find the energy of photon corresponding to longest wavelength.

MEDIUM

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

Hydrogen (₁H¹), Deuterium (₁H²), singly ionised Helium (₂He⁴)⁺ and doubly ionised lithium (₃Li⁶)⁺⁺ all have one electron around the nucleus. Consider an electron transition from

n = 2

n = 1

. If the wave lengths of emitted radiation are

λ_{1}, λ_{2}, λ_{3}

and

λ_{4}

respectively then approximately which one of the following is correct ?

Hydrogen alpha emission line emitted from a galaxy, corresponding to Balmer series transition from n=3 to n=2, is found to be Doppler shifted to 652.4nm. It can be concluded that the galaxy is R=1.097×107 m-1

Important Questions on Atomic Physics

Learn and Prepare for any exam you want !

Hydrogen alpha emission line emitted from a galaxy, corresponding to Balmer series transition from $n = 3$ to $n = 2$ , is found to be Doppler shifted to $652.4 nm$ . It can be concluded that the galaxy is

$R = 1.097 \times 10^{7} m^{- 1}$