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Hydrogen atom in ground state is excited by a monochromatic radiation of λ=975. Number of spectral lines in the resulting spectrum emitted will be R=1.09×107 m-1

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Important Questions on Atomic Physics

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Given the value of Rydberg constant is 107 m-1, the wave number of the last line of the Balmer series in hydrogen spectrum will be:
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If an electron in a hydrogen atom jumps from the 3rd orbit to the 2nd orbit, it emits a photon of wavelength λ. When it jumps from the 4th orbit to the 3rd orbit, the corresponding wavelength of the photon will be
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The ratio of kinetic enerav to the total energy of an electron in a Bohr orbit of the hydrogen atom, is
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In a hydrogen like atom electron make transition from an energy level with quantum number nn to another with quantum number (n−1) if n>>1, the frequency of radiation emitted is proportional to :
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Find the energy required for the electron excitation in Li2+from the first to the third Bohr orbit .

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The hydrogen atom is excited from the ground state to another state with the principal quantum number equal to 4. Then, the number of spectral lines in the emission spectra will be
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As an electron makes a transition from an excited state to the ground state of a hydrogen like atom/ion
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An electron bean is acceleration by a potential difference V to hit a metallic target to produce X-rays. It produces continuous as well as characteristic X-rays. If λmin is the smallest possible wavelength of λmin ray in the spectrum, the variation of log λmin with logVis correctly represented in