EASY
Earn 100

Identify random variables as either discrete or continuous in each of the following situation. Also write the range wherever it is possible. Number of students present in a class of 50 students.

Important Questions on Probability Distributions

HARD
Suppose A is 3×3 matrix consisting of integer entries that are chosen at random from the set -1000,-999,999,1000. Let P be the probability that either A2=-I or A is diagonal, where I is the 3×3 identity matrix. Then,
MEDIUM

A random variable X has the following probability distribution

X 1 2 3 4 5 6 7
P(X) K-1 3K K 3K 3K2 K2 K2+K
MEDIUM
Let xi1i10 be ten observation of a random variable X. If i=110xi-p=3 and i=110xi-p2=9 where 0pR, then the standard deviation of these observations is:
 
MEDIUM
From a lot of 30 bulbs which include 6 defectives, a sample of 4 bulbs are drawn at random with replacement. Find the probability distribution of the number of defective bulbs.
MEDIUM
A box contains 6 pens, 2 of which are defective. Two pens are taken randomly from the box. If random variable x: Number of defective pens obtained, then standard deviation of x=
MEDIUM

For the probability distribution given by

X=xi 0 1 2
Pi 25/36 5/18 1/36

The standard deviation σ is

HARD
If 'X' has a binomial distribution with parameters n=6, p and P(X=2)=12, P(X=3)=5, then p=
HARD
A cubical die is thrown. Find the mean and variance of X, giving the number on the face that shows up.
MEDIUM
A boy tosses fair coin 3 times. If he gets ₹ 2x for x heads then his expected gain equals to ₹........
MEDIUM
An unbiased coin is tossed 5 times. Suppose that a variable X is assigned the value k when k consecutive heads are obtained for k=3,4,5, otherwise X takes the value -1. Then the expected value of X, is
EASY

A random variable X has the probability distribution :

X 1 2 3 4 5 6 7 8
PX 0.15 0.23 0.12 0.10 0.20 0.08 0.07 0.05

For the events E=X is a prime number and F=X<4, then PEF is
MEDIUM

A random variable X has the following probability mass function

X -2 3 1
PX=x λ6 λ4 λ12

Then the value of λ is 

MEDIUM
A random variable X takes the values 0,1,2. Its mean is 1.2 if PX=0=0.3, then PX=1= 
EASY

Given below is the probability distribution of discrete random variable X

X=x 1 2 3 4 5 6
PX=x K 0 2K 5K K 3K

Then, PX4=

MEDIUM

A random variable X has the following probability distribution:

X=xi -2 -1 0 1 2
PX=xi 16 k 14 k 16

The variance of this random variable is

MEDIUM

A random variable X has the following probability distribution.

X=x01234567P(X=x)0k2k2k3kk22k27k2+k

Find k. [Write your answer in decimal]

MEDIUM

A random variable X has the following probability distribution.

X=x01234567P(X=x)0k2k2k3kk22k27k2+k

Find k. [Write your answer in decimal]

EASY
A random variable X has the following probability distribution:
X:12345PX: k22kk2k5k2
Then, PX>2 is equal to:
HARD
In a game, a man wins Rs. 100 if he gets 5 or 6 on a throw of a fair die and loses Rs. 50 for getting any other number on the die. If he decides to throw the die either till he gets a five or a six or to a maximum of three throws, then his expected gain/loss (in rupees) is :
MEDIUM
A die is rolled. If X denotes the number of positive divisors of the outcome then the range of the random variable X is