Identify the common factor of $6, 25, \text{and} 12$ 

${\left(9\right)}^{11}\times {\left(5\right)}^7\times {\left(7\right)}^5\times {\left(3\right)}^2\times {\left(17\right)}^2$

Consider the following statements in respect of all factors of $360$:

1. The number of factors is $24$.

2. The sum of all factors is $1170$.

Which of the above statements is/are correct?

The prime factorisation of 240 is:

(A) $2^3\times$$3^2\times 5$ 

(B) $2^4\times 3^2\times 5$

(C) $2^4\times 3\times 5$

(D) $2^5\times 3\times 5$

The total number of factors of 1156 is: 

(A) 9 

(B) 8 

(C) 10 

(D) 11 

Which of the following statement(s) is/are true?

I. There are $12$ multiples of $9$ from $7$ to $109.$

II. There are $9$ multiples of $13$ from $19$ to $119.$

The sum of all the factors of $156$ is: 
(A) $392$
(B) $235$
(C) $390$
(D) $379$

What is the number of Prime factor in ${15}^{18}$$\times$$4^{10}$$\times$$6^9$.