If \( cosec39^0=x \) , the value of \( \frac{1}{cosec^251^0}+\sin^239^0+\tan^251^0-\frac{1}{\sin^251^0\sec^239^0} \)  is.

Find the value of following equation:

${\left(\sec \varnothing -\tan \varnothing \right)}^2{\left(1+\sin \varnothing \right)}^2÷{\sin }^2 \varnothing =?$

If $3\sin \theta =2{\cos }^2\theta , 0^0<\theta <{90}^0$. Then the value of $({\tan }^2\theta +se{c}^2\theta -\cos e{c}^2\theta )$ is: