If $\alpha , \beta$ are the zeros of the polynomial $f\left(x\right)=x^2-p\left(x+1\right)-c$ such that $\left(\alpha +1\right)\left(\beta +1\right)=0,$ then $c=$

If the diagram shows the graph of the polynomial $f\left(x\right)=a{x}^2+bx+c$, then

Figure below shows the graph of the polynomial $f\left(x\right)=a{x}^2+bx+c$ for which