If $\mathrm{A}=\left(\begin{array}{ll}6& 2\\ 7& -5\end{array}\right)$ and $\mathrm{A}-\mathrm{B}=\left(\begin{array}{cc}-2& 1\\ 4& -9\end{array}\right)$, then $\mathrm{B}=$

Important Questions on Matrices and Determinants

EASY

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 17 - Matrices and Determinants>KEAM 2020>Q 2

If $\left[\begin{array}{cc}-1& 3\\ 4& -5\\ 0& 2\end{array}\right]\left[\begin{array}{cc}1& 2\\ 0& 7\end{array}\right]=\left[\begin{array}{cc}-1& 19\\ \alpha & -27\\ 0& 14\end{array}\right]$, then the value of $\mathrm{\alpha }$ is

MEDIUM

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 17 - Matrices and Determinants>KEAM 2019>Q 3

If $AB=A$ and $BA=B,$ then $A^2,B^2$ is equal to

EASY

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 17 - Matrices and Determinants>KEAM 2018>Q 4

If $\left[\begin{array}{ccc}1& x& 1\end{array}\right]\left[\begin{array}{ccc}1& 3& 2\\ 2& 5& 1\\ 15& 3& 2\end{array}\right]\left[\begin{array}{c}1\\ 2\\ x\end{array}\right]=0$$,$ then $x$ can be

HARD

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 17 - Matrices and Determinants>KEAM 2019>Q 5

If $\left|\begin{array}{lll}1& a& a^2\\ 1& x& x^2\\ b^2& ab& a^2\end{array}\right|=0$, then $x=$

MEDIUM

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 17 - Matrices and Determinants>KEAM 2019>Q 6

A determinant of second order is made up of elements $0$ and $1.$ The number of determinants with non-negative values is

MEDIUM

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 17 - Matrices and Determinants>KEAM 2018>Q 7

If $\left|\begin{array}{ccc}x& 2& x\\ x^2& x& 6\\ x& x& 6\end{array}\right|=a{x}^4+b{x}^3+c{x}^2+dx+e$$,$ then $5a+4b+3c+2d+e$ is equal to

MEDIUM

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 17 - Matrices and Determinants>KEAM 2020>Q 8

The value of the determinant $\left|\begin{array}{ccc}\mathrm{bc}& \mathrm{ca}& \mathrm{ab}\\ {\mathrm{a}}^3& {\mathrm{b}}^3& {\mathrm{c}}^3\\ \frac{1}{\mathrm{a}}& \frac{1}{\mathrm{b}}& \frac{1}{\mathrm{c}}\end{array}\right|$ is

EASY

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 17 - Matrices and Determinants>KEAM 2020>Q 9

If the matrix $\left[\begin{array}{ccc}1& 2& -1\\ -3& 4& \mathrm{k}\\ -4& 2& 6\end{array}\right]$ is singular, then the value of $\mathrm{k}$ is equal to