If $a+b+c=0$, then what is the value of ${\left(a+b-c\right)}^3+{\left(b+c-a\right)}^3+{\left(c+a-b\right)}^3$?

Divide:

$\left(x^3+1\right)$ by $\left(x+1\right)$

Divide:

$\left(-6y^2+29y-28\right)$ by $\left(3y-4\right)$

Divide:

$\left(4x^2+3x+\frac{1}{2}\right)$ by $\left(2x+1\right)$

Divide:

$\left(x^3-1\right)$ by $\left(x-1\right)$

Divide:

$\left(71y-24y^3-21-31y^2\right)$ by $\left(3-8y\right)$

Divide: $\left(y^4+y^3+y+y^5+1+y^2\right)$ by $\left(y^3+1\right)$

Divide: $\left(2y^2+y-2y^3+y^4+4\right)$ by $\left(y^2+y+1\right)$

Divide: $\left(x^3-6x^2+11x-6\right)$ by $\left(x^2-5x+6\right)$