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If a lighter body (mass M1 and velocity V1 ) and a heavier body (mass M2 and velocity Vi) have the same kinetic energy, then

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Important Questions on Centre of Mass, Momentum and Collisions

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A bomb of mass 12 kg at rest explodes into two fragments of masses in the ratio 1:3. The kinetic energy of the smaller fragment is 216 J. The momentum of the heavier fragment is (in kg m s-1)
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A bomb is projected with 200 m s-1 at an angle 60° with horizontal. At the highest point, it explodes into three particles of equial masses. One goes vertically upward with velocity 100 m s-1, second particle goes vertically downyard with, the same velocity as the first. Then what is the velocity of the third one-
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Consider the following two statements :
A. Linear momentum of a system of particles is zero
B. Kinetic energy of a system of particles is zero
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A 50 g bullet moving with velocity 10 m s-1 strikes a block of 950 g at rest and gets embedded in it. The loss in kinetic energy will be?

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A body at rest splits into three parts of masses m, m and 4m, respectively. The two equal masses fly off perpendicular to each other, and each with speed of v. The speed of 4m will be
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A stationary body explodes into two fragments of masses m1 and m2. If momentum of one fragment is p, the minimum energy of explosion is 
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If the momentum of a body increases by 20%, the percentage increase in its kinetic energy is equal to
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A man of mass m climbs on a rope of length L suspended below a balloon of mass M. The balloon is stationary with respect to the ground. If the man begins to climb up the rope at a speed vrel (relative to the rope), then in what direction and with what speed (relative to the ground) will the balloon move?