If a pure chlorophyll solution is illuminated with ultraviolet light, the solution appears:

Study the following lists and match the discoveries and/or inventions made by the scientists during ${20}^{\text{th }}$ century

The correct answer is

Assertion $\left(\mathrm{A}\right):$ In $\mathrm{PS} \mathrm{I}$, the reaction centre, chlorophyll 'a' has an absorption peak at $700 \mathrm{nm}$, hence is called $\mathrm{P}700$, while in $\mathrm{PS} \mathrm{II}$, it has absorption maxima at $680 \mathrm{nm}$ and is called $\mathrm{P}680$.

Reason $\left(\mathrm{R}\right):$ Calvin pathways occur in all photosynthetic plants, it does not matter where they have ${\mathrm{C}}_3$ or ${\mathrm{C}}_4$ pathways and the Calvin cycle described in three stages: Carboxylation, reduction and regeneration.

The correct answer is:

Arrange the path of electrons from water to the phycocyanin in the light reaction.

i) Plastoquinone

ii) Excited ${\mathrm{P}}_{680*}$

iii) Cyt $f$

iv) $\mathrm{Fe}-\mathrm{S}$

v) Pheophytin

vi) Quinone

The correct sequence is

The graph below represents the absorption spectrum of a major pigment contributing to photosynthesis.

Which one of the following best represents the photosynthetic efficiency of the pigment?