If $n$ drops of a liquid, each with surface energy $E\mathit{,}$ join to form a single drop, then

The surface energy of a liquid drop is u. If it is split into $1000$ equal droplets, then its surface energy becomes

The work done in splitting a drop of water of $1 \mathrm{mm}$ Radius into $64$ Identical droplets are (S.T. of water is $72\times {10}^{-3} \mathrm{J} {\mathrm{m}}^{-2}$)

A spherical liquid drop of the radius $R$ is divided into eight equal droplets. If the surface tension is $T$, then the work done in this process will be

A drop of liquid of diameter $2.8 \mathrm{mm}$ Breaks up into $125$ Identical droplets. The change in energy is nearly (S.T. of liquid$=75 \mathrm{dyne} {\mathrm{cm}}^{-1}$)

Let $T_1$ Be surface tension between solid and air, $T_2$ Be the surface tension between solid and liquid and $T$ Be the surface tension between liquid and air. Then in equilibrium, for a drop of liquid on a clean glass plate, the relation is ($\mathrm{\theta }$ Is the angle of contact)

The excess pressure in a soap bubble of diameter $8\mathrm{cm}$ and surface tension $0.02 \mathrm{N} {\mathrm{m}}^{-1},$ is