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If n drops of potential V merge, find new potential on the big drop.

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Important Questions on Electrostatics

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Two conducting spheres of redii R1 and R2 respectively are charged and joined by a wire. The ratio of electric fields of spheres is
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Charge on a sphere of radius R is q and on the sphere of radius 2R is -2q. If these spheres are connected through a conducting wire then, amount of charge flown through a wire will be:
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Two identical conducting spheres R and S have negative charges Q1 and Q2 respectively, but Q1Q2. The spheres are brought to touch each other and then kept in their original positions, now the force between them is
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27 smaller drop combine to form a bigger drop if potential on smaller drop is V then potential on bigger drop will be-
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Find the electrostatic potential at a point P at a distance R2 from the centre of the shell is, when a thin spherical conducting shell of radius R has a charge q. Another charge Q is placed at the centre of the shell.
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A charged oil drop is suspended in uniform field of 3×104 V m-1 so that it neither falls nor rises. The charge on the drop will be:

(Take the mass of the charge =9.9×10-15 kg and g=10 m s-2)
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Two thin wire rings each having a radius R are placed at a distance d apart with their axes coinciding. The charges on the two rings +q and -q. The potential difference between the centres of the two rings is
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An electric charge 10-3 μC is placed at the origin 0, 0 of x-y co-ordinate system. Two points A and B are situated at 2, 2 and 2, 0 respectively. The potential difference between the points A and B will be