HARD
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If the (m+1)th ,(n+1)th  and (r+1)th  terms of an A.P. are in G.P. and m, n, r are in H.P., then which of the following is correct?

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Important Questions on Sequences and Series

HARD
The number of real solutions of the equation sin-1i=1xi+1-xi=1x2i=π2-cos-1i=1 -x2i-i=1-xi lying in the interval -12,12 is____.

(Here, the inverse trigonometric functions sin-1x & cos-1x assume values in -π2,π2 & 0,π

respectively.)
HARD

If m is the A.M. of two distinct real numbers I and n I, n>1  and G1, G2 and G3 are three geometric means between I and n, then G14+2G24+G34 equals

MEDIUM
Let a, b and c be the 7th, 11th and 13th terms respectively of a non-constant A.P. If these are also the three consecutive terms of a G.P., then ac is equal to:
MEDIUM
Three positive numbers form an increasing G.P. If the middle term in this G.P. is doubled, the new numbers are in A.P. Then the common ratio of the G.P. is :
EASY
If a>1,b>1 and c>1 are in geometric progression, then 11+logea,11+logeb,11+logec will be in
MEDIUM
The sum of the 3rd and the 4th terms of a G.P. is 60 and the product of its first three terms is 1000. If the first term of this G.P. is positive, then its 7th term is:
HARD
Let bi>1 for i=1, 2,.,101. Suppose logeb1,logeb2,..,logeb101 are in Arithmetic Progression (A.P.) with the common difference loge2.  Suppose a1, a2,.,a101 are in A.P. such that a1=b1 and a51=b51. If t=b1+b2++b51 and s=a1+a2++a51, then
MEDIUM
The sum of the first 20 terms of the series 1+32+74+158+3116+ is
MEDIUM
If a,b,c are in arithmetic progression, then abc,1c,2b will be in
MEDIUM
If x, y, z are in HP, then logx+z+logx-2y+z is equal to 
MEDIUM
Suppose p, q, r are real numbers such that q=p4-p, r=q4-q, p=r4-r. The maximum possible value of p+q+r is
HARD
If a1,a2,a3,.,an are in HP and fk= r=1nar-ak, then a1f1,a2f2,a3f3,,anfn are in 
MEDIUM
The quotient when 1+x2+x4+...+x34 is divided by 1+x+x2+...+x17 is
MEDIUM
The sum of first 20 terms of the sequence 0.7, 0.77, 0.777, ......, is :
HARD
Let x,y,z be three non-negative integers such that x+y+z=10. The maximum possible value of xyz+xy+yz+zx is
HARD

Let S1 be the sum of areas of the squares whose sides are parallel to coordinate axes. Let S2 be the sum of areas of the slanted squares as shown in the figure. Then S1/S2 is

Question Image

MEDIUM
Let f:xy be such that f1=2 and fx+y=fxfy for all natural numbers x and y . If k=1 n f( a+k )=16( 2 n 1 ) then a is equal to
EASY
If b+c-aa,c+a-bb,a+b-cc are in AP, then a,b,c are in
MEDIUM
If ax=by=cz, where x,y,z are unequal positive numbers and a,b,c are in GP, then
MEDIUM
If cos(x-y),cosx and cos(x+y) are in HP, then cosxsec(y/2) is equal to