EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 9 - Circle>TS EAMCET 2020 (9-Sep Shift-1)>Q 20

HARD

TS EAMCET

IMPORTANT

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If the circle $S \equiv x^{2} + y^{2} - 4 = 0$ intersects another circle $S^{'} = 0$ of radius $\frac{5 \sqrt{2}}{2}$ in such a manner that the common chord is of maximum length with slope equal to $\frac{1}{4},$ then the centre of $S^{'} = 0$ is

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Important Questions on Circle

HARD

TS EAMCET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 9 - Circle>TS EAMCET 2020 (9-Sep Shift-1)>Q 21

If the angle between the circles

x^{2} + y^{2} - 4 x - 6 y + k = 0

and

x^{2} + y^{2} + 8 x - 4 y + 11 = 0

is

\frac{π}{3},

then a value of

k

is

EASY

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IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 9 - Circle>TS EAMCET 2018 (04-May Shift-1)>Q 22

If the circles given by

S \equiv x^{2} + y^{2} - 14 x + 6 y + 33 = 0

and

S^{'} \equiv x^{2} + y^{2} - a^{2} = 0 (a \in N)

have

4

common tangents, then the possible number of circles

S^{'} = 0

is

MEDIUM

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IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 9 - Circle>TS EAMCET 2018 (04-May Shift-1)>Q 23

The center of the circle passing through the point

(1, 0)

and cutting the circles

x^{2} + y^{2} - 2 x + 4 y + 1 = 0

and

x^{2} + y^{2} + 6 x - 2 y + 1 = 0

orthogonally is

MEDIUM

TS EAMCET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 9 - Circle>TS EAMCET 2018 (04-May Shift-1)>Q 24

The equation of the tangent at the point

(0, 3)

on the circle which cuts the circles

x^{2} + y^{2} - 2 x + 6 y = 0, x^{2} + y^{2} - 4 x - 2 y + 6 = 0

and

x^{2} + y^{2} - 12 x + 2 y + 3 = 0

orthogonally is

HARD

TS EAMCET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 9 - Circle>TS EAMCET 2019 (03-May Shift-2)>Q 25

The condition for the circles

x^{2} + y^{2} + a x + 4 = 0

and

x^{2} + y^{2} + b y + 4 = 0

to touch each other is

HARD

TS EAMCET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 9 - Circle>TS EAMCET 2019 (03-May Shift-2)>Q 26

If the equation of the circle which passes through the point

(1, 1)

and cuts both the circles

x^{2} + y^{2} - 4 x - 6 y + 4 = 0

and

x^{2} + y^{2} + 6 x - 4 y + 15 = 0

orthogonally is

x^{2} + y^{2} + 2 g x + 2 f y + c = 0,

then

5 g + 2 f + c =

EASY

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IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 9 - Circle>TS EAMCET 2021 (04-Aug Shift-1)>Q 27

The number of possible common tangents that can be drawn to the circles

x^{2} + y^{2} + 4 x - 6 y - 3 = 0

and

x^{2} + y^{2} + 4 x - 2 y + 1 = 0

is

MEDIUM

TS EAMCET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 9 - Circle>TS EAMCET 2021 (04-Aug Shift-2)>Q 28

The internal centre of similitude of the two circles

x^{2} + y^{2} - 4 x - 6 y + 12 = 0,

x^{2} + y^{2} + 4 x - 2 y - 4 = 0

is