If the coefficients of $x$ and $y$ in the two linear equations are interchanged, then solution can be obtained in the following way:
Let the two simultaneous linear equations in $x$ and $y$ be
$ax + by = c$...$\left(1\right)$ and $bx + ay=d$...$\left(2\right)$
Then, $\left(1\right)+\left(2\right)\Rightarrow (a+b)x+(a+b)y=c+d\Rightarrow x+y=\frac{c+d}{a+b}...\left(3\right)$
Again, $\left(1\right)-\left(2\right)\Rightarrow (a+b)x-(a+b)y=c-d\Rightarrow x-y=\frac{c-d}{a-b}...\left(4\right)$
Now, $\left(3\right)+\left(4\right)\Rightarrow 2x=\frac{c+d}{a+b}+\frac{c-d}{a-b}\Rightarrow x=\frac{1}{2}\left(\frac{c+d}{a+b}+\frac{c-d}{a-b}\right)$
$\left(3\right)-\left(4\right)\Rightarrow y=\frac{1}{2}\left(\frac{c+d}{a+b}-\frac{c-d}{a-b}\right)$

Now, answer the following question,
The solution of $37x+41y=70, 41x+37y=86$ is,