If the container is accelerating along a direction as shown in figure. Find the angle $\theta$ made by liquid surface as shown.

 

Liquid filled in the container has density $5 {\mathrm{kgm}}^{-3}$. If the container is moving horizontally with acceleration $a=$ $2 {\mathrm{ms}}^{-2}$ then pressure difference between two points $A$ and $B$, which are at the same level with separation between them $50\mathrm{cm}$, will be

When at rest, a liquid stands at the same level in the tube shown in figure. But as indicated a height difference $h$ occurs when the system is given an acceleration a towards the right. Then $h$ is equal to

A body having volume $V$ is floating, fully submerged in a liquid of density $\rho$. If the container starts moving upward with constant acceleration $\frac{g}{3}$ then the buoyant force acting on the body will become

Find the pressure difference between $A$ and $B$.

If container is accelerated towards right with acceleration $a=g$. Find pressure at $A$.

It is desired to design an air plane with a "lift" of $1000 \mathrm{~N}$ per square meter of wing area. If the velocity of streamline flow past the lower wing surface is $100 \mathrm{~m} / \mathrm{s}$, then the required velocity over the upper surface is (given density of air is $1.3 \mathrm{~kg} \mathrm{~m}^{-3}$ )