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If the diameter of earth becomes half(mass remains unchanged), then the acceleration due to gravity at surface of earth becomes

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Important Questions on Gravitation

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Dependence of intensity of gravitational field E of earth with distance r from centre of earth is correctly represented by:
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The acceleration due to gravity at a height 1 km above the earth is the same as at a depth d below the surface of earth. Then
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The value of acceleration due to gravity at Earth's surface is  9.8 m s-2 . The altitude above its surface at which the acceleration due to gravity decreases to  4.9 m s-2, is close to: (Radius of earth  =6.4×106 m )
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The value of the acceleration due to gravity is g1 at a height h=R2 (R= radius of the earth) from the surface of the earth. It is again equal to g1 at a depth d below the surface the earth. The ratio dR equals:
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The variation of acceleration due to gravity g  with distance d from the centre of the earth is best represented by (R= Earth's radius):
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The height h at which the weight of a body will be the same as that at the same depth h from the surface of the earth is,

(Radius of the earth is R and effect of the rotation of the earth is neglected) 

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A body weighs 200 N on the surface of the earth. How much will it weigh half way down to the centre of the earth?
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The ratio of accelerations due to gravity g1:g2 on the surfaces of two planets is 5: 2 and the ratio of their respective average densities ρ1:ρ2 is 2: 1 .What is the ratio of respective escape velocities v1:v2 from the surface of the planets?
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The depth d at which the value of acceleration due to gravity becomes 1n times the value at the earth's surface is (R = radius of the earth )
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A ball is launched from the top of Mount Everest which is at an elevation of 9000 m. The ball moves in a circular orbit around the earth. The acceleration due to gravity near the earth's surface is g. The magnitude of the ball's acceleration while in orbit is,
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A body weighs 72 N on the surface of the earth. What is the gravitational force on it, at a height equal to half the radius of the earth?
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If the change in the value of g at a height h above the surface of the earth is the same as at a depth x below it, then (both x and h being much smaller than the radius of the earth)
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The value of acceleration due to gravity at a height of 10 km from the surface of earth is x. At what depth inside the earth is the value of the acceleration due to gravity has the same value x?
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A solid sphere of mass M and radius a is surrounded by a uniform concentric spherical shell of thickness 2a and mass 2M. The gravitational field at distance 3a from the centre will be:
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The ratio of the height above the surface of earth to the depth below the surface of earth, for gravitational accelerations to be the same (assuming small heights), is
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Which of the following graphs correctly represents the variation of 'g' on the Earth?
HARD
A spiral galaxy can be approximated as an infinitesimally thin disc of a uniform surface mass density (mass per unit area) located at z=0, Two stars A and B start from rest from heights 2z0 and z0 (z0<< radial extent of the disc), respectively and fall towards the disc, cross over to the other side and execute periodic oscillations. The ratio of time periods of A and B is
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The mass density of a spherical body is given by ρr=kr for rR and ρr=0 for r>R, where r is the distance from the center. The correct graph that describes qualitatively the acceleration, a of a test particle as a function of r is:
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Starting from the center of the earth having radius, R, the variation of g (acceleration due to gravity) is shown by
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At what height from the surface of earth the gravitation potential and the value of g are -5.4×10J kg-2 and 6.0 s-2 respectively? Take the radius of earth as 6400 km: