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If the earth of radius R, while rotating with angular velocity ω, becomes stand still, what will be the effect on the weight of a body of mass m at a latitude of 45°?

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Important Questions on Gravitation

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A body weighs 63 N on the surface of the Earth. At a height h above the surface of Earth, its weight is 28 N while at a depth h below the surface of the Earth, the weight is 31.5 N. The value of h is
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If the earth were assumed to have uniform density and spherical symmetry, then the value of g in m s-2 halfway towards the centre of earth would be g=10 m s-2
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It is given, R is the radius of the earth and ω is its angular velocity and gp is the value of g at the poles. The effective value of g at the latitude ϕ=60° will be equal to
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What should be the angular speed of the earth in rad s-1 so that a body of 5 kg weighs zero at the equator?

[Take g=10 m s-2 and radius of earth =6400 km]

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The acceleration due to gravity at a height 120th of the radius of the earth above the earth surface is 9 m s-2. Its value at a point at an equal distance below the surface of the earth in m s-2 is about?  (Take the value of g at the earth's surface as 10 m s-2)
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Considering earth's rotation, the value of g at the earth's surface is
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If the earth rotates faster than its present speed, the weight of an object will
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The rotation of the earth having radius R about its axis speed up to a value such that a man at latitude angle 60°feels weightlessness. The duration of the day in such a case is