If the electric field at a distance $x$ from the origin is given as $E=\frac{100}{x^2}$, then the potential difference between the points situated at $x=10 \mathrm{m}$ and $x=20 \mathrm{m}$ is,

In the region where the electric field is zero, the relation between the electric potential $V$ and distance $r$ is,

A graph of the $x$ component of the electric field as a function of $x$ in a region of space is shown. The $y$ and $z$ components of the electric field are zero in this region. If the electric potential is $10 \mathrm{V}$ at the origin, then the potential at $x=2.0 \mathrm{m}$ is 

In an electric field region, the electric potential varies along the $x$-axis as shown in the graph. The $x$ components of the electric field in the regions for the intervals $PQ$ and $QR$ as marked in the graph, respectively, are 

An electric field is given by $E_{\mathrm{x}}=-\left(2x^3\right)\hat{\mathrm{i}} \mathrm{N} {\mathrm{C}}^{-1}$. What is the potential at the point $(1, -2)$ if the potential at a point $(2, 4)$ is taken to be zero?

The electric field intensity at all the points in space is given by $\overrightarrow{E}=\left(\sqrt{3}\hat{\mathrm{i}}-\hat{\mathrm{j}} \right) \mathrm{V} {\mathrm{m}}^{-1}$. The nature of equipotential lines in the $x-y$ plane is given by,