If the equation $x^2+y^2-4x-6y-12=0$ is transformed to $X^2+Y^2=25$ when the axes are translated to a point then the new coordinates of (-3, 5) are

If ${\theta }_1,{\theta }_2,{\theta }_3$ are respectively the angles by which the coordinate axes are to be rotated to eliminate the $xy$ term from the following equations, then the descending order of these angles is

$A_1=3x^2+5xy+3y^2+2x+3y+4=0$
$A_2=5x^2+2\sqrt{3}xy+3y^2+6=0$

$A_3=4x^2+\sqrt{3}xy+5y^2-4=0$

For $a>b>c>0$, the distance between $(1,1)$ and the point of intersection of the lines $ax+by+c=0$ and $bx+ay+c=0$ is less than $2\sqrt{2}$. Then