If the principal value of ${\tan }^{-1}\left(1\right)$ is $\frac{\mathrm{\pi }}{k}$, find the value of $k$.

The principal value of: ${\cos }^{-1}\left(-\frac{\sqrt{3}}{2}\right)$ is $\frac{m\pi }{6}$then $m=$

Principal value of ${\tan }^{-1}\left(\sqrt{3}\right)=m°$, $m=$

Principal value of ${cosec}^{-1}(-\sqrt{2})=k°$, $k=$