If $x^2+y^2=1,$ then $\frac{d^{2}x}{d{y}^2}=$

Important Questions on Differentiation

MEDIUM

MHT-CET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 16 - Differentiation>MHT-CET 2018>Q 4

If ${\log }_{10}\left(\frac{x^3-y^3}{x^3+y^3}\right)=2$, then $\frac{dy}{dx}=$

MEDIUM

MHT-CET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 16 - Differentiation>MHT-CET 2017>Q 5

If $g\left(x\right)$ is the inverse function of $f\left(x\right)$ and $f^{\text{'}}\left(x\right)=\frac{1}{1+x^4},$ then $g^{\text{'}}\left(x\right)$ is

MEDIUM

MHT-CET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 16 - Differentiation>MHT-CET 2020 (12-Oct Shift-1)>Q 6

If $y={\tan }^{-1}\left(\sec x+\tan x\right)$, then $\frac{dy}{dx}=$

EASY

MHT-CET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 16 - Differentiation>MHT-CET 2019>Q 7

If $x=\mathrm{s}\mathrm{i}\mathrm{n}\theta , y={\mathrm{s}\mathrm{i}\mathrm{n}}^3\theta ,$ then $\frac{d^{2}y}{d{x}^2}$ at $\theta$ = $\frac{\pi }{2}$ is ….

MEDIUM

MHT-CET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 16 - Differentiation>MHT-CET 2018>Q 8

If $x=e^{\theta }\left(\sin \theta -\cos \theta \right)$ , $y=e^{\theta }\mathrm{ }\left(\sin \theta +\cos \theta \right)$ then $\frac{dy}{dx}$ at $\theta =\frac{\pi }{4}$ is

MEDIUM

MHT-CET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 16 - Differentiation>MHT-CET 2017>Q 9

If $x=f\left(t\right)$ and $y=g\left(t\right)$ are differentiable functions of $t$ then $\frac{d^{2}y}{d{x}^2}$ is

MEDIUM

MHT-CET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 16 - Differentiation>MHT-CET 2017>Q 10

If $x=a\left(t-\frac{1}{t}\right), y=a\left(t+\frac{1}{t}\right)$ where $t$ be the parameter then $\frac{dy}{dx}=?$

EASY

MHT-CET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 16 - Differentiation>MHT-CET 2019>Q 11

If then $\mathrm{}{x}^y=e^{x-y},$ then $\frac{dy}{dx}$ at $x=1$ is ….