If $y={\tan }^{-1}\left\{\frac{\sqrt{1+x^2}-\sqrt{1-x^2}}{\sqrt{1+x^2}+\sqrt{1-x^2}}\right\}$ then find $\frac{dy}{dx}$

Find $\frac{dy}{dx}$ in the following case:

$y=e^{2x}$

Find $\frac{dy}{dx}$ in the following case: $y=x{e}^x$

Find $\frac{dy}{dx}$ in the following case: $y=x^2·2^x$

Find $\frac{dy}{dx}$ in the following case: $y=x^3 \log x$

Find $\frac{dy}{dx}$ in the following case: $y=e^x \log x$

Find $\frac{dy}{dx}$ in the following case: $y=5^x \log x$

Find $\frac{dy}{dx}$ in the following case: $y=e^x \tan x$

Find $\frac{dy}{dx}$ in the following case: $y=2^x \sin x$