In FM, frequency deviation is

Consider an optical communication system operating at $\lambda \sim 800 \mathrm{nm} .$ Suppose only $1 \%$ of the optical source frequency is the available channel bandwidth for optical communication. How many channels can be accommodated for transmitting audio signals requiring a bandwidth of $8 \mathrm{kHz}$ ?

(Speed of light$=3\times {10}^8 \mathrm{m} {\mathrm{s}}^{-2}$)

A telephone link is operating at a central frequency of $10 \mathrm{GHz}$. If $1 \%$ of this is available then how many telephone channels can be simultaneously given when each telephone covers a band width of $5 \mathrm{kHz}$ ?

Assertion: FM broadcast is preferred over AM broadcast.

Reason: The process of combining the message signals with carrier-wave is called demodulation.

The process of regaining of information from carrier wave at the receiver is termed as

In communication system, the process of superimposing a low frequency signal on a high frequency wave is known as

The radio waves of frequency $300\, \mathrm{MHz}$ to $3000\,\rm{MHz}$ belong to

The attenuation in optical fibre is mainly due to,