Match the genetic phenomena with their respective ratios Column - I Column -II A. Inhibitory gene ratio 1 . 9 : 3 : 4 B. Complementary gene ratio 2 . 1 : 1 : 1 : 1 C. Recessive epistasis ratio 3 . 12 : 3 : 1 D. Dihybrid test cross ratio 4 . 13 : 3 E. Dominant epistasis ratio 5 . 9 : 7

A - 4 , B - 5 , C - 1 , D - 2 , E - 3

A - 5 , B - 4 , C - 3 , D - 2 , E - 1

A - 1 , B - 2 , C - 4 , D - 3 , E - 5

A - 2 , B - 1 , C - 4 , D - 5 , E - 3

A - 5 , B - 4 , C - 1 , D - 2 , E - 3

A tall true breeding garden pea plant is crossed with a dwarf true breeding garden pea plant. When the F 1 plants were selfed the resulting genotypes were in the ratio

1 : 2 : 1 :: Tall homozygous : Tall heterozygous : Dwarf

1 : 2 : 1 :: Tall heterozygous : Tall homozygous : Dwarf

E M B I B E

NTA Errorless Biology Volume-2>Chapter 5 - Principles of Inheritance and Variation>Ordinary Thinking>Q 110

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In Mendelian dihybrid cross when heterozygous Round Yellow are self crossed, Round Green offsprings are represented by the genotype

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Important Questions on Principles of Inheritance and Variation

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NTA Errorless Biology Volume-2>Chapter 5 - Principles of Inheritance and Variation>Ordinary Thinking>Q 111

If a cross is made between

AA

and aa, the nature of

F_{1}

progeny will be

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NTA Errorless Biology Volume-2>Chapter 5 - Principles of Inheritance and Variation>Ordinary Thinking>Q 112

When a tall plant with rounded seeds

(TTRR)

is crossed with a dwarf plant with wrinkled seeds

(ttrr)

, the

F_{1}

generation consists of tall plants with rounded seeds. How many types of gametes an

F_{1}

plant would produce

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NTA Errorless Biology Volume-2>Chapter 5 - Principles of Inheritance and Variation>Ordinary Thinking>Q 113

In a plant red fruit (R) is dominant over yellow fruit (r) and tallness (T) is dominant over shortness (t). If a plant with RRTt genotype is crossed with a plant that is rrtt :-

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NTA Errorless Biology Volume-2>Chapter 5 - Principles of Inheritance and Variation>Ordinary Thinking>Q 114

A self-fertilizing trihybrid plant forms

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NTA Errorless Biology Volume-2>Chapter 5 - Principles of Inheritance and Variation>Ordinary Thinking>Q 115

Match the genetic phenomena with their respective ratios

	Column - I		Column -II
A.	Inhibitory gene ratio	$1$ .	$9 : 3 : 4$
B.	Complementary gene ratio	$2$ .	$1 : 1 : 1 : 1$
C.	Recessive epistasis ratio	$3$ .	$12 : 3 : 1$
D.	Dihybrid test cross ratio	$4$ .	$13 : 3$
E.	Dominant epistasis ratio	$5$ .	$9 : 7$