Describe and compare the geometries of the molecules and the hybridization of the carbon and boron atoms in F 2 C = C = CF 2 and F 2 B - C ≡ C - BF 2 . Compare the relative orientation of the sets of fluorine atoms in the two cases. In which case is it impossible for all four fluorine atoms to lie in the same plane?

F 2 C = C = C = CF 2 All fluorine atoms do not lie in a plane molecule because of 3 D geometry of orbitals. Whereas all fluorine atoms can lie in the same plane.

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JEE Advanced

IMPORTANT

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In ${SF}_{4}$ molecule, the lone pair of electrons occupies an equatorial position rather than an axial position in the overall trigonal bipyramidal arrangement. Why?

Important Questions on Chemical Bonding and Molecular Structure

MEDIUM

JEE Advanced

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Chapterwise/Topicwise Daily Practice Problems (DPP) Inorganic Chemistry Part - 1 JEE Main & Advanced>Chapter 2 - Chemical Bonding and Molecular Structure>DPP>Q 1

A molecule of

{PCl}_{5}

exists, but that of

{NCl}_{5}

does not. Why?

MEDIUM

JEE Advanced

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Chapterwise/Topicwise Daily Practice Problems (DPP) Inorganic Chemistry Part - 1 JEE Main & Advanced>Chapter 2 - Chemical Bonding and Molecular Structure>DPP>Q 2

Discuss the structures of the following molecule:

$HCP$

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JEE Advanced

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Chapterwise/Topicwise Daily Practice Problems (DPP) Inorganic Chemistry Part - 1 JEE Main & Advanced>Chapter 2 - Chemical Bonding and Molecular Structure>DPP>Q 2

Discuss the structures of the following molecule.

${IOF}_{4}^{-}$ .

EASY

JEE Advanced

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Chapterwise/Topicwise Daily Practice Problems (DPP) Inorganic Chemistry Part - 1 JEE Main & Advanced>Chapter 2 - Chemical Bonding and Molecular Structure>DPP>Q 2

Discuss the structures of the following molecule.

${SeOCl}_{2}$

MEDIUM

JEE Advanced

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Chapterwise/Topicwise Daily Practice Problems (DPP) Inorganic Chemistry Part - 1 JEE Main & Advanced>Chapter 2 - Chemical Bonding and Molecular Structure>DPP>Q 3

Describe and compare the geometries of the molecules and the hybridization of the carbon and boron atoms in

F_{2} C

= C = {CF}_{2}

and

F_{2} B - C \equiv C - {BF}_{2} .

Compare the relative orientation of the sets of fluorine atoms in the two cases. In which case is it impossible for all four fluorine atoms to lie in the same plane?

MEDIUM

JEE Advanced

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Inorganic Chemistry Part - 1 JEE Main & Advanced>Chapter 2 - Chemical Bonding and Molecular Structure>DPP>Q 4

In certain polar solvent,

{PCl}_{5}

undergoes an ionisation reaction, in which

{Cl}^{-}

ion leaves one

{PCl}_{5}

molecule and attaches itself to another.

2 {PCl}_{5} ⇌ {PCl}_{4}^{+} + {PCl}_{6}^{-}

What are the changes in the geometrical shapes that occur in this ionisation?

EASY

JEE Advanced

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Inorganic Chemistry Part - 1 JEE Main & Advanced>Chapter 2 - Chemical Bonding and Molecular Structure>DPP>Q 5

What hybrid orbitals are ascribed to carbon in the (short-lived)

{CH}_{2}^{2 +}

ions? What is the geometry of this ion?

MEDIUM

JEE Advanced

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Chapterwise/Topicwise Daily Practice Problems (DPP) Inorganic Chemistry Part - 1 JEE Main & Advanced>Chapter 2 - Chemical Bonding and Molecular Structure>DPP>Q 6

The Hybridization of the nitrogen atom and electrons geometry around the nitrogen atom in pyridine is ______.

In SF4 molecule, the lone pair of electrons occupies an equatorial position rather than an axial position in the overall trigonal bipyramidal arrangement. Why?

Important Questions on Chemical Bonding and Molecular Structure

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In ${SF}_{4}$ molecule, the lone pair of electrons occupies an equatorial position rather than an axial position in the overall trigonal bipyramidal arrangement. Why?