In Young's double slit experiment, one of the slit is wider than other, so that amplitude of the light from one slit is double of that from other slit. If $I_{\mathrm{m}}$ be the maximum intensity, the resultant intensity $I$ when they interfere at phase difference $\phi$ is given by 

In Young's double slit experiment, the intensity on the screen at a point where path difference $\lambda$ is $K$. What will be the intensity at the point where path difference is $\frac{\lambda }{4}?$ 

The intensity at a point where the path difference is $\frac{\lambda}{6}(\lambda=$ wavelength of light $)$ is $I$. If $I_0$ is the maximum intensity, then$\frac{I}{I_0}$ is equal to

In Young's double slit experiment, the two slits act as coherent sources of equal amplitude $A$ and wavelength $\lambda$. In another experiment with the same set up the two slits are of equal amplitude $A$ and wavelength $\lambda$  but are incoherent. The ratio of the intensity of light at the mid-point of the screen in the first case to that in the second case is 

The intensity at the maximum in a Young's double slit experiment is $I_0$. Distance between two slits is $\mathrm{d}=5 \lambda,$ where $\lambda$ is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance $D=10 \mathrm{d} ?$

In a Young's double-slit experiment, bi-chromatic light of wavelengths $400 \mathrm{nm}$ and $560 \mathrm{nm}$ are used. The distance between the slits is $0.1 \mathrm{mm}$ and the distance between the plane of the slits and the screen is $1 \mathrm{m}$. The minimum distance between two successive regions of complete darkness is

In Young's double slit experiment, intensity at a point is $\frac{1}{4}$ of the maximum intensity. Angular position of this point is 

In a double slit experiment, the two slits are $1 \mathrm{mm}$ apart and the screen is placed $1 \mathrm{m}$ away. A monochromatic light of wavelength $500 \mathrm{nm}$ is used. What will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single slit pattern? 

In Young's double slit experiment the separation $d$ between the slits is $2 \mathrm{mm},$ the wavelength $\lambda$ of the light used is$5896 \mathrm{\AA }$ and distance $D$ between the screen and slits is $100 \mathrm{cm}.$ It is found that the angular width of the fringes is $0.20^{\circ} .$ To increase the fringe angular width to $0.21^{\circ}$ (with same $\lambda$ and $D$ ) the separation between the slits needs to be changed to