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Earn 100

In ____________ mode of vibration a 33 cm long organ pipe resonates at a frequency of 1000 Hz. (Velocity of sound = 330 m/s)

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Important Questions on Waves

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Physics Crash Course NEET>Chapter 11 - Waves>Level 2>Q 47

When the stationary waves are formed, then

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Physics Crash Course NEET>Chapter 11 - Waves>Level 2>Q 48
In a standing wave on a string rigidly fixed at both ends:
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Physics Crash Course NEET>Chapter 11 - Waves>Level 3>Q 1
The length of a sonometer wire is either 95 cm or 100 cm. In both the cases, if a tuning fork produces 4 beats per second, then the frequency of the tuning fork is
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Physics Crash Course NEET>Chapter 11 - Waves>Level 3>Q 2
If two tuning forks A and B are sounded together, they produce 4 beats per second. A is then slightly loaded with wax, they produce same beats when sounded again. The frequency of A is 256 Hz. The frequency of B will be :-
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Physics Crash Course NEET>Chapter 11 - Waves>Level 3>Q 3
You are given four tuning forks, the lowest frequency of the forks is 300 Hz. By striking two tuning forks at a time, any of 1, 2, 3, 5, 7 and 8 beat frequencies are heard. The possible frequencies of the other three forks are
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Physics Crash Course NEET>Chapter 11 - Waves>Level 3>Q 4
The lengths of two closed organ pipes are 0.750 m and 0.770 m. If they are sounded together in fundamental mode, 3 beats s-1 are produced. The velocity of sound will be
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Physics Crash Course NEET>Chapter 11 - Waves>Level 3>Q 5
Two closed organ pipes, when sounded simultaneously, gave 4 beats per s. If the longer pipe has a length of 1 m, then, the length of the shorter pipe will be (v=300 m s-1)
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Physics Crash Course NEET>Chapter 11 - Waves>Level 3>Q 6
In the physics pratical, 26 tuning forks are arranged in the decreasing order of their frequencies. The first one is octave of the last one. If each tuning fork gives 3 beats with the next, Find the frequency of 18th tuning fork ?