MEDIUM
10th CBSE
IMPORTANT
Earn 100

In a class test, the sum of the marks obtained by P in mathematics and science is 28. Had he got 3 more marks in mathematics and 4 marks less in science, the product of marks obtained in the two subjects would have been 180. Find the marks obtained by him in the two subjects separately.

Important Questions on Quadratic Equations

HARD
10th CBSE
IMPORTANT
Secondary School Mathematics for Class 10>Chapter 4 - Quadratic Equations>Exercise 4E>Q 36

A man buys a number of pens for ₹180. If he had bought 3 more pens for the same amount, each pen would have cost him ₹3 less. How many pens did he buy?

HARD
10th CBSE
IMPORTANT
Secondary School Mathematics for Class 10>Chapter 4 - Quadratic Equations>Exercise 4E>Q 37
A dealer sells an article for ₹75 and gains as much percent as the cost price of the article. Find the cost price of the article.
HARD
10th CBSE
IMPORTANT
Secondary School Mathematics for Class 10>Chapter 4 - Quadratic Equations>Exercise 4E>Q 38
One year ago, man was 8 times as old as his son. Now, his age is equal to the square of his son’s age. Find their present ages.
HARD
10th CBSE
IMPORTANT
Secondary School Mathematics for Class 10>Chapter 4 - Quadratic Equations>Exercise 4E>Q 38
A man is 312 times as old as his son. If the sum of the squares of their ages is 1325, find the ages of the father and the son.
HARD
10th CBSE
IMPORTANT
Secondary School Mathematics for Class 10>Chapter 4 - Quadratic Equations>Exercise 4E>Q 39
The sum of reciprocals of Meena’s ages (in years) 3 years ago and 5 years hence is 13. Find her present age.
HARD
10th CBSE
IMPORTANT
Secondary School Mathematics for Class 10>Chapter 4 - Quadratic Equations>Exercise 4E>Q 40
The sum of the ages of a boy and his brother is 25 years, and the product of their ages in years is 126. Find their ages.
HARD
10th CBSE
IMPORTANT
Secondary School Mathematics for Class 10>Chapter 4 - Quadratic Equations>Exercise 4E>Q 41
The product of Tanvy’s age (in years) 5 years ago and her age is 8 years later is 30. Find her present age.
MEDIUM
10th CBSE
IMPORTANT
Secondary School Mathematics for Class 10>Chapter 4 - Quadratic Equations>Exercise 4E>Q 42
Two years ago, man’s age was three times the square of his son’s age. In three years’ time, his age will be four time his son’s age. Find their present ages.