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In a coaxial, straight cable, the central conductor and the outer conductor carry equal currents in opposite directions. The magnetic field is non-zero 

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Important Questions on Magnetic Effect of Current

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A cylindrical wire of radius R is carrying uniformly distributed current i cross–section. If a circular loop of radius r is taken as amperian loop, then the variation value of B.dl over this loop with radius ‘ r’ of loop will be best represented by
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A current I flows along the length of an infinitely long, straight, thin walled pipe. Then
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A long solenoid carrying a current produces a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved, the new value of magnetic field will be equal to
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A long, thick straight conductor of radius R carries current I uniformly distributed in its cross section area. The ratio of energy density of the magnetic field at distance R/2 from surface inside the conductor and outside the conductor is :
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A coaxial cable is made up of two conductors. The inner conductor is solid and is of radius R1 the outer conductor is hollow of inner radius R2 and outer radius R3. The space between the conductors is filled with air. The inner and outer conductors are carrying currents of equal magnitudes and in opposite directions. Then the variation of magnetic field with distance from the axis is best plotted as 

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When a charged particle moves at right angles to a magnetic field, then which of the following quantities changes,
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A proton, a deuteron and an α-particle are accelerated through the same potential difference, and then they enter a uniform normal magnetic field. If the radius of circular path of proton is 8 cm then the radius of circular path of deuteron will be 
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A proton and an α-particle enter a uniform magnetic field at right angles to it with same velocity. The time period of α particle as compared to that of proton, will be