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In a collision between two solid spheres, the velocity of separation along the line of impact is (assume no external forces act on the system of two spheres during impact)

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Important Questions on Centre of Mass, Momentum and Collisions

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In the figure shown the block A collides head on with another block B at rest. Mass of B is twice the mass of A. The block A stops after collisión. The co-efficient of restitution is

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A sphere of mass m moving with a constant velocity hits another stationary sphere of the same mass. If e is the coefficient of restitution, then the ratio of the speed of the first sphere to the speed of the second sphere, after a collision, will be
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A ball rebounds after colliding with the floor, then in case of inelastic collision-
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A particle of mass m1 moving with a velocity of 5 m s-1 collides head-on with a stationary particle of mass m2. After collision both the particles move with a common velocity of 4 m s-1, then the value of m1m2 is-
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A body of mass m1 collidés head on elastically with a stationary body of mass m2. If velocities of m1 before and after the collision are v and -v3, respectively then the value of m1m2 is 
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Two identical smooth spheres A and B are moving with same velocity and collides with similar spheres C and D, then after elastics collision- (Consider one dimensional collision)

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A ball is allowed to fall from a height 1.0 m. If the value of the coefficient of restitution is 0.6, then after the impact ball will go up to
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A ball of mass m is moving with velocity v collides elastically with another ball of identical mass coming from opposite direction with velocity 2v. Their velocities after collision will be