Two molecules of a gas have speeds of 9 × 10 6 m s - 1 and 1 × 10 6 m s - 1 , respectively. What is the RMS speed of these molecules?

Here, we use RMS velocity formula as given below, v r m s = v 1 2 + v 2 2 + . . . . . . . . . . + v n 2 n In our case, we have only two molecules with speeds, v 1 = 9 × 10 6 m s - 1 v 2 = 1 × 10 6 m s - 1 ∴ v r m s = 9 × 10 6 2 + 1 × 10 6 2 2 v r m s = 81 × 10 12 + 1 × 10 12 2 = 10 12 ( 81 + 1 ) 2 = 10 6 82 2 = 10 6 41 = 10 6 × 6 . 4 v r m s = 6 . 4 × 10 6 m s - 1

E M B I B E

NCERT Exemplar Physics - Class 11>Chapter 13 - Kinetic Theory>MCQ-II>Q 13.11

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In a diatomic molecule, the rotational energy at a given temperature

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Important Questions on Kinetic Theory

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NCERT Exemplar Physics - Class 11>Chapter 13 - Kinetic Theory>MCQ-II>Q 13.12

Which of the following diagrams depicts ideal gas behaviour?

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NCERT Exemplar Physics - Class 11>Chapter 13 - Kinetic Theory>MCQ-II>Q 13.13

When an ideal gas is compressed adiabatically, its temperature rises: the molecules on the average have more kinetic energy than before. The kinetic energy increases.

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NCERT Exemplar Physics - Class 11>Chapter 13 - Kinetic Theory>VSA>Q 13.14

Calculate the number of atoms in

39.4

gold. Molar mass of gold is

197 g m o l e^{- 1}

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NCERT Exemplar Physics - Class 11>Chapter 13 - Kinetic Theory>VSA>Q 13.15

The volume of a given mass of a gas at

27 ° C, 1 atm i s 100 cc

. What will be its volume at

327 ° C

?

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NCERT Exemplar Physics - Class 11>Chapter 13 - Kinetic Theory>VSA>Q 13.16

The molecules of a given mass of a gas have root mean square speeds of

100 m s^{- 1}

at 27^{°} C

and

1.00

atmospheric pressure. What will be the root mean square speeds of the molecules of the gas at

127 ° C

and

2.0

atmospheric pressure?

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NCERT Exemplar Physics - Class 11>Chapter 13 - Kinetic Theory>VSA>Q 13.17

Two molecules of a gas have speeds of

9 \times 10^{6} m s^{- 1} and 1 \times 10^{6} m s^{- 1}

, respectively. What is the RMS speed of these molecules?

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NCERT Exemplar Physics - Class 11>Chapter 13 - Kinetic Theory>VSA>Q 13.18

A gas mixture consists of

2

moles of oxygen and

4

moles of neon at temperature T. Neglecting all vibrational modes, calculate the total internal energy of the system. (Oxygen has two rotational modes.)

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NCERT Exemplar Physics - Class 11>Chapter 13 - Kinetic Theory>VSA>Q 13.19

Calculate the ratio of the mean free paths of the molecules of two gases having molecular diameters