
In a double slit experiment, instead of taking slits of equal widths, one slit is made twice as wide as the other. Then, in the interference pattern,

Important Questions on Interference and Diffraction
To increase fringe width, by keeping distance between slit and screen constant, we need to ensure that,

In Young's double slit experiment, If a third slit is made in between the double slits then?

Two coherent light sources and are apart from each other. The screen is placed at a distance of from the sources. The width of the fringes on the screen should be,

In a certain double slit experimental arrangement, interference fringes of width each are observed when light of wavelength is used. Keeping the set-up unaltered, if the source is replaced by another source of wavelength , the fringe width will be,

In a Young's double slit experiment, the fringe width is found to be . If the whole apparatus is immersed in water of refractive index without disturbing the geometrical arrangement, the new fringe width will be,

In Young's double slit experiment, if $L$ is the distance between the slits and the screen upon which interference pattern is observed, is the average distance between the adjacent fringes and being the slit separation, the wavelength of light is given by,

In Young's double slit experiment carried out with light of wavelength , the distance between the slits is and the screen is at from the slits. The central maximum is at . The third maximum (taking the central maximum as zeroth maximum) will be at equal to

In a double slit experiment with monochromatic light, fringes are obtained on a screen placed at some distance from the slits. If the screen is moved by towards the slits, the change in fringe width is . If the separation between the slits is , then the wavelength of light used is
