Gamma Question Bank for Medical Chemistry>Chapter 1 - Some Basic Concepts of Chemistry>Assignment Set-2>Q 9

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Earn 100

In a reaction $3 A + B_{2} \to A_{3} B_{2}$ If $180$ atoms of $A$ and $100$ molecules of $B$ react, then

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Important Questions on Some Basic Concepts of Chemistry

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Gamma Question Bank for Medical Chemistry>Chapter 1 - Some Basic Concepts of Chemistry>Assignment Set-2>Q 10

Copper has two naturally occurring isotopes

{}^{63}{Cu}

and

{}^{65}{Cu}

. If the average atomic mass of copper is

63.546 u

, then natural abundance of lighter isotope of

Cu

will be

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Gamma Question Bank for Medical Chemistry>Chapter 1 - Some Basic Concepts of Chemistry>Assignment Set-2>Q 11

Out of the following statements choose an incorrect statement regarding compounds

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Gamma Question Bank for Medical Chemistry>Chapter 1 - Some Basic Concepts of Chemistry>Assignment Set-2>Q 15

28 g

of

N_{2}

and

6 g

of

H_{2}

react to give

34 g

of

{NH}_{3}

. This statement illustrates the law of

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Gamma Question Bank for Medical Chemistry>Chapter 1 - Some Basic Concepts of Chemistry>Assignment>Q 1

The total number of electrons in

4.2 g

of

N^{3 -}

ion is (

N_{A}

is the Avogadro's number):

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Gamma Question Bank for Medical Chemistry>Chapter 1 - Some Basic Concepts of Chemistry>Assignment>Q 2

Suppose that

A

and

B

form the compounds

B_{2} A_{3}

and

B_{2} A

. If

0.05 mole

of

B_{2} A_{3}

weighs

9 g

and

0.1 mole

of

B_{2} A

weighs

10 g

, the atomic weight of

A

and

B

respectively are

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Gamma Question Bank for Medical Chemistry>Chapter 1 - Some Basic Concepts of Chemistry>Assignment>Q 3

Number of

Fe

atoms in

100 g

Haemoglobin if it contains

0.33 % Fe

. (Atomic mass of

Fe = 56

)

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Gamma Question Bank for Medical Chemistry>Chapter 1 - Some Basic Concepts of Chemistry>Assignment>Q 4

The number of electrons in

1.6 g

of

{CH}_{4}

is approximately

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Gamma Question Bank for Medical Chemistry>Chapter 1 - Some Basic Concepts of Chemistry>Assignment>Q 5

Specific volume of cylindrical virus particle is $6 .02 \times 10^{- 2} cc / gm$ , whose radius and length is $7 Å & 10 Å$ , respectively. If $N_{A} = 6 .02 \times 10^{23}$ , find the molecular weight of the virus