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In a series LR circuit, the voltage drop across inductor is 8 volt and across resistor is 6 volt. Then voltage applied and power factor of circuit respectively are:

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Important Questions on Alternating Current

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IMPORTANT
In an a.c. circuit the e.m.f. e and the current i at any instant are given respectively by:
e=E0sinωt
i=I0sinωt-ϕ
The average power in the circuit over one cycle of a.c. is :
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The power factor of an AC circuit having resistance R and inductance L connected in series and an angular velocity ω is
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The average power delivered to a series AC circuit is given by (symbols have their usual meaning):
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The potential difference V across and the current I flowing through an instrument in an AC circuit are given by:

V=5cosωt volt

I=2sinωt A

The power dissipated in the instrument is :

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A direct current of 2 A and an alternating current having a maximum value of 2 A flow through two identical resistances. The ratio of heat produced in the two resistances will be,
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A sinusoidal AC current flows through a resistor of resistance R. If the peak current is Ip, then average power dissipated is: 
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If a current i given by i=i0sinωt-π2 flows in an A.C. circuit across which an A.C. potential of e=e0sinωt has been applied, then the power consumption P in the circuit will be:
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If the frequency of the source emf in an AC circuit is n, the power varies with a frequency :