Alpha Question Bank for Engineering: Chemistry>Chapter 5 - Equilibrium>Exercise-2>Q 78

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Earn 100

In a solution obtained by mixing $100 mL$ of $0.25 M$ Triethylamine $(K_{b} = 6.4 \times 10^{- 5}) & 400 mL$ of $\frac{M}{18} {NH}_{4}$ $OH (K_{b} = 1.8 \times 10^{- 5})$ $:$

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Important Questions on Equilibrium

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Alpha Question Bank for Engineering: Chemistry>Chapter 5 - Equilibrium>Exercise-2>Q 79

Ratio of

[{HA}^{2 -}]

in

1 L

of

0.1 M H_{3} A

solution

(K_{a_{1}} = 10^{- 5}; K_{a_{2}} = 10^{- 8} & K_{a_{3}} = 10^{- 11}) &

upon addition of

0.1 mole

HCl

to it will be :

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Alpha Question Bank for Engineering: Chemistry>Chapter 5 - Equilibrium>Exercise-2>Q 82

Calculate

[H^{+}]

in a

0.2 M

solution of dichloroacetic acid

(K_{a} = 5 \times 10^{- 2})

that also contains

0.05 M H_{2} {SO}_{4}

. Report your answer after multiplying it by

400

.

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Alpha Question Bank for Engineering: Chemistry>Chapter 5 - Equilibrium>Exercise-2>Q 86

The

pH

of a solution resulting from the addition of

12.5 ml

of

0.1 M HCl

to

50 ml

of a solution containing

0.15 M {CH}_{3} COOH & 0.2 M {CH}_{3} COONa

will be (Given :

{pK}_{a}

of

{CH}_{3} COOH = 4.74

)

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Alpha Question Bank for Engineering: Chemistry>Chapter 5 - Equilibrium>Exercise-2>Q 87

What

%

of the carbon in the

H_{2} {CO}_{3} - {HCO}_{3}^{-}

buffer should be in the form of

{HCO}_{3}^{-}

so as to have a neutral solution?

(K_{a} = 4 \times 10^{- 7})

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Alpha Question Bank for Engineering: Chemistry>Chapter 5 - Equilibrium>Exercise-2>Q 88

Buffer capacity of a buffer solution is

x

, the volume of

1 M NaOH

added to

100 mL

of this solution if change the

pH

by

1

is:

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Alpha Question Bank for Engineering: Chemistry>Chapter 5 - Equilibrium>Exercise-2>Q 90

100 m L

of

0.02 M

benzoic acid

({pK}_{a} = 4.2)

is titrated using

0.02 M

N a O H

.

pH

after

50 m L

and

100 m L

of

N a O H

have been added are

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Alpha Question Bank for Engineering: Chemistry>Chapter 5 - Equilibrium>Exercise-2>Q 91

Which of the following solutions have different $pH$ ?

$(i)$ $100 mL$ of $0.2 M HCl + 100 mL$ of $0.4 M {NH}_{3}$

$(ii)$ $50 mL$ of $0.1 M HCl + 50 mL$ of $0.2 M {NH}_{3}$

$(iii)$ $100 mL$ of $0.3 M HCl + 100 mL$ of $0.6 M {NH}_{3}$

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Alpha Question Bank for Engineering: Chemistry>Chapter 5 - Equilibrium>Exercise-2>Q 92

Upon titrating a solution of weak monoprotic acid with a weak monoacidic base solution, at equivalence point: