Beta Question Bank for Medical: Chemistry>Chapter 8 - Solutions>EXERCISE-I (Conceptual Questions)>Q 4

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In a solution of $7.8 g$ benzene $(C_{6} H_{6})$ and $46.0 g$ toluene $(C_{6} H_{5} C H_{3})$ , the mole fraction of benzene is

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Beta Question Bank for Medical: Chemistry>Chapter 8 - Solutions>EXERCISE-I (Conceptual Questions)>Q 5

An X molal solution of a compound in benzene has mole-fraction of solute equal to 0.2, The value of X is:

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Beta Question Bank for Medical: Chemistry>Chapter 8 - Solutions>EXERCISE-I (Conceptual Questions)>Q 7

H_{2} O_{2}

solution which is used for hair bleaching, is sold as a solution of approximately

5.0 g H_{2} O_{2}

per

100 mL

of the solution (molecular mass of

H_{2} O_{2} =34

). The molarity of this hair bleaching solution is approximately

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Beta Question Bank for Medical: Chemistry>Chapter 8 - Solutions>EXERCISE-I (Conceptual Questions)>Q 9

A molal solution is one that contains one mole of solute in

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Beta Question Bank for Medical: Chemistry>Chapter 8 - Solutions>EXERCISE-I (Conceptual Questions)>Q 10

Which of the following statement is true :-
$(a)$ Molarity is the no. of moles of solute dissolved per litre of solvent.
$(b)$ The molarity and normality of a solution of sodium carbonate are same.
$(c)$ Molality $(m)$ of a solution is defined as the number of moles of solute dissolved is $1000 gm$ of solution.

$(d)$ The ratio of mole fraction of solute and solvent is in the ratio of their respective moles.

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Beta Question Bank for Medical: Chemistry>Chapter 8 - Solutions>EXERCISE-I (Conceptual Questions)>Q 11

Molar concentration of a solution in water is:

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Beta Question Bank for Medical: Chemistry>Chapter 8 - Solutions>EXERCISE-I (Conceptual Questions)>Q 13

Henry's law constant for dissolution of

{CH}_{4}

in benzene at

298 K

is

2 \times 10^{5} mm

of

Hg

. Then solubility of

{CH}_{4}

in benzene at

298 K

under

760 mm

of

Hg

is:

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Beta Question Bank for Medical: Chemistry>Chapter 8 - Solutions>EXERCISE-I (Conceptual Questions)>Q 15

1 mole

of heptane (

V . P . = 92 mm

of

Hg

) was mixed with

4 moles

of octane (

V . P . = 31 mm

of

Hg

). The vapour pressure of resulting ideal solution is:

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Beta Question Bank for Medical: Chemistry>Chapter 8 - Solutions>EXERCISE-I (Conceptual Questions)>Q 16

At $88 ° C$ benzene has a vapour pressure of $900$ torr and toluene has a vapour pressure of $360$ torr. What is the mole fraction of benzene in the mixture with toluene that will boil at $88 ° C$ at $1 atm$ pressure. (Benzene - Toluene form an ideal solution):