Let f : R → R be given by f x = x - 1 x - 2 x - 5 . Define F x = ∫ 0 x f t d t , x > 0 . Then which of the following options is/are correct?

F has two local maxima and one local minimum in 0 , ∞

MEDIUM

Earn 100

In an A.P., the sixth terms $a_{6} = 2$ . If the $a_{1} a_{4} a_{5}$ is the greatest, then the common difference of the A.P., is equal to

70.53% studentsanswered this correctly

Important Questions on Application of Derivatives

HARD

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

The maximum value of

f (x) = \frac{\log x}{x} (x \neq 0, x \neq 1)

HARD

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

A solid hemisphere is mounted on a solid cylinder, both having equal radii. If the whole solid is to have a fixed surface area and the maximum possible volume, then the ratio of the height of the cylinder to the common radius is

MEDIUM

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

Twenty meters of wire is available for fencing off a flower-bed in the form of a circular sector. Then the maximum area (in sq. m) of the flower-bed, is:

HARD

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

Let

f (x) = α x^{2} - 2 + \frac{1}{x}

where

α

is a real constant. The smallest

α

for which

f (x) \geq 0

for all

x > 0

is-

HARD

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

If the function

f

given by

f (x) = x^{3} - 3 (a - 2) x^{2} + 3 a x + 7

, for some

a \in R

is increasing in

(0, 1]

and decreasing in

[1, 5)

, then a root of the equation,

\frac{f (x) - 14}{{(x - 1)}^{2}} = 0, (x \neq 1)

is :

HARD

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

A rectangular sheet of fixed perimeter with sides having their lengths in the ratio $8 : 15$ is converted into an open rectangular box by folding after removing squares of equal area from all four corners. If the total area of removed squares is $100$ , the resulting box has maximum volume. Then the lengths of the sides of the rectangular sheet are:

HARD

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

The maximum area of a rectangle that can be inscribed in a circle of radius

2

units is

HARD

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

The minimum distance of a point on the curve

y = x^{2} - 4

from the origin is

HARD

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

The maximum area (in sq. units) of a rectangle having its base on the

x -

axis and its other two vertices on the parabola,

y = 12 - x^{2}

such that the rectangle lies inside the parabola, is :

HARD

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

Let

k

and

K

be the minimum and the maximum values of the function

f (x) = \frac{{(1 + x)}^{0.6}}{1 + x^{0.6}} in [0, 1]

, respectively, then the ordered pair

(k, K)

is equal to:

MEDIUM

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

If non-zero real numbers

b

and

c

are such that

m i n f (x) > m a x g (x)

, where

f (x) = x^{2} + 2 b x + 2 c^{2}

and

g (x) = - x^{2} - 2 c x + b^{2}, (x \in R)

; then

|\frac{c}{b}|

lies in the interval

HARD

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

The maximum value of

f (x) = \frac{x}{4 + x + x^{2}}

[- 1, 1]

HARD

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

Let

f (x) = x^{2} + \frac{1}{x^{2}}

and

g (x) = x - \frac{1}{x}, x \in R - \{- 1, 0, 1\} .

h (x) = \frac{f (x)}{g (x)}

, then the local minimum value of

h (x)

is:

EASY

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

The maximum value of the function

f (x) = 2 x^{3} - 15 x^{2} + 36 x + 4

is attained at

MEDIUM

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

A wire of length

2

units is cut into two parts which are bent respectively to form a square of side

= x

units and a circle of radius

= r

units. If the sum of the areas of the square and the circle so formed is minimum, then

HARD

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

Let

f : R \to R

be given by

f (x) = (x - 1) (x - 2) (x - 5) .

Define

F (x) = \int_{0}^{x} f (t) d t, x > 0 .

Then which of the following options is/are correct?

HARD

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

The point on the curve

x^{2} = 2 y

which is nearest to the point

(0, 5)

MEDIUM

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

x = - 1

and

x = 2

are extreme points of

f (x) = α \log |x| + β x^{2} + x

, then

MEDIUM

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

From the top of a

64

metres high tower, a stone is thrown upwards vertically with the velocity of

48 m / s .

The greatest height (in metres) attained by the stone, assuming the value of the gravitational acceleration

g = 32 m / s^{2}

, is:

MEDIUM

Mathematics>Differential Calculus>Application of Derivatives>Critical Point

The least value of

α \in R

for which,

4 α x^{2} + \frac{1}{x} \geq 1,

for all

x > 0,

In an A.P., the sixth terms a6=2. If the a1a4a5 is the greatest, then the common difference of the A.P., is equal to

Important Questions on Application of Derivatives

Learn and Prepare for any exam you want !

In an A.P., the sixth terms $a_{6} = 2$ . If the $a_{1} a_{4} a_{5}$ is the greatest, then the common difference of the A.P., is equal to