A parallel plate capacitor with air between the plates has a capacitance of 8 pF ( 1 pF = 10 - 12 F ) . What will be the capacitance of the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6 ?

C = ε ο A d C = 8 p F = 8 × 10 - 12 F ε ο A d = 8 × 10 - 12 L e t t h e n e w c a p a c i tan c e b e C ' C ' = ε o k A d ' , n o w , k = 6 , d ' = d / 2 ∴ C ' = ε o × 6 × A d / 2 = 12 × ε o A d = 12 × 8 × 10 - 12 = 96 × 10 - 12 F = 96 p F .

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Gamma Question Bank for Medical Physics>Chapter 17 - Electrostatic Potential and Capacitance>EXERCISE>Q 8

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In an arrangement of two concentric conducting shells, with centre at origin and radii $a$ and $b$ $(a < b)$ , charges $Q_{1}$ and $Q_{2}$ are given to inner and outer shell, then the potential $V$ at a distance $r$ from the origin is $(r < a)$

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Important Questions on Electrostatic Potential and Capacitance

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Gamma Question Bank for Medical Physics>Chapter 17 - Electrostatic Potential and Capacitance>EXERCISE>Q 9

Two concentric conducting spheres of radii $R$ and $2 R$ are carrying charges $Q$ and $- 2 Q$ respectively. If the charge, on inner sphere is doubled, the potential difference between the two spheres will

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Gamma Question Bank for Medical Physics>Chapter 17 - Electrostatic Potential and Capacitance>EXERCISE>Q 10

A hollow conducting sphere is placed in an electric field produced by a point charge at $P$ as shown in the figure. Let $V_{A}$ and $V_{B}$ be the electrostatic potential at points $A$ and $B$ respectively. Then,

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