EASY
VITEEE
IMPORTANT
Earn 100

In an irreversible process taking place at constant T and P and in which only the pressure-volume work is being done, the change in Gibbs free energy (dG) and the change in entropy (dS) satisfy the criteria

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Important Questions on Thermodynamics

EASY
VITEEE
IMPORTANT
What is the change in entropy when ice melts at 0°C, enthalpy of fusion of one mole of ice is 6.02 kJ mol-1?
MEDIUM
VITEEE
IMPORTANT
What is the free energy change for the conversion of 1 mole of water into steam at 373.2 K. The heat of vaporization Hv of water at 373.2 K is 9.1 kcal mol-1. The entropy change is 25.5 cal mol-1 K-1.
HARD
VITEEE
IMPORTANT
Match List I (Equations) with List II (Types of process) and select the correct option.
List-I
(Equations)
List-II
(Types of process)
A. Kp>Q 1.

Non-spontaneous

B. ΔG°<RT ln Q 2.

Equilibrium

C. KP=Q 3. Spontaneous and endothermic
D. T>ΔHΔS 4. Spontaneous
HARD
VITEEE
IMPORTANT

The factor of ΔG values is important in metallurgy. The ΔG values for the following reactions at 800°C are given as:

S2 s+2O2 g2SO2 g; ΔG=-544 kJ
2Zn s+S2 s2ZnS s; ΔG=-293 kJ
2Zn s+O2 g2ZnO s; ΔG=-480 kJ

ΔG for the below reaction will be

2ZnS s+3O2 g2ZnO s+2SO2 g

MEDIUM
VITEEE
IMPORTANT

PbO2PbO; ΔG298 K<0SnO2SnO; ΔG298 K>0

The most probable oxidation state of Pb and Sn will be

HARD
VITEEE
IMPORTANT
The densities of graphite and diamond at 298 K are 2.25 and 3.31 g cm-3, respectively. If the standard free energy difference ΔG° is equal to 1895 J mol-1, the pressure at which graphite will be transformed into diamond at 298 K is