HARD

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In graphite, the electrons are

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Important Questions on The p-Block Elements

EASY

Chemistry>Inorganic Chemistry>The p-Block Elements>Allotropes of Carbon

Assertion: Among the carbon allotropes, diamond is an insulator, whereas, graphite is a good conductor of electricity.

Reason: Hybridization of carbon in diamond and graphite are

s p^{3}

and

s p^{2}

respectively.

EASY

Chemistry>Inorganic Chemistry>The p-Block Elements>Allotropes of Carbon

The number of six membered and five membered rings in Buckminster Fullerence respectively is

MEDIUM

Chemistry>Inorganic Chemistry>The p-Block Elements>Allotropes of Carbon

Choose the correct statement:

HARD

Chemistry>Inorganic Chemistry>The p-Block Elements>Allotropes of Carbon

White phosphorus on reaction with concentrated

N a O H

solution in an inert atmosphere of

C O_{2}

gives phosphine and compound

(X) . (X)

on acidification with

H C l

gives compound

(Y) .

The basicity of compound

(Y)

is:

EASY

Chemistry>Inorganic Chemistry>The p-Block Elements>Allotropes of Carbon

In diamond, the hybridization of each carbon atom is

EASY

Chemistry>Inorganic Chemistry>The p-Block Elements>Allotropes of Carbon

Match list-I with List-II :

List - I	List - II
A. Coke	I. Carbon atoms are ${sp}^{3}$ hybridised
B. Diamond	II. Used as dry lubricants
C. Fullerene	III. Used as a reducing agent
D. Graphite	IV. Cage like molecules

Choose the correct answer from the options given below:

MEDIUM

Chemistry>Inorganic Chemistry>The p-Block Elements>Allotropes of Carbon

Diamond is extremely hard whereas graphite is soft. This is because

EASY

Chemistry>Inorganic Chemistry>The p-Block Elements>Allotropes of Carbon

The element that does NOT exhibits allotropy is-

EASY

Chemistry>Inorganic Chemistry>The p-Block Elements>Allotropes of Carbon

What is the hybridization of carbon atoms in fullerene?

EASY

Chemistry>Inorganic Chemistry>The p-Block Elements>Allotropes of Carbon

Identify the correct statements regarding fullerene.

$i .$ It has $60$ vertices.
$ii .$ All the carbon atoms are in the ${sp}^{3}$ hybridisation.
$iii .$ The number of rings having six carbons each is $20$ and the number of rings having five carbons each is $12$ .
$iv .$ All the $C - C$ bond lengths in it are equal.