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In the Bohr's model of the hydrogen atom, the lowest orbit corresponds to

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Important Questions on Atoms

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The following statements are given about the Hydrogen atom.

A. The wavelengths of the spectral lines of the Lyman series are greater than the wavelength of the second spectral line of the Balmer series.

B. The orbits correspond to circular standing waves in which the circumference of the orbit equals a whole number of wavelengths.
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Figure shows the energy levels PQRS and G of an atom, where G is the ground state. A red line in the emission spectrum of the atom can be obtained by an energy level change from Q to S. A blue line can be obtained by the following energy level change

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The figure indicates the energy level diagram of an atom and the origin of five spectral lines in emission spectra. Which of the spectral lines will also occur in the absorption spectra?

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Consider the following two statements:
(A) Line spectra contain information about atoms.
(B) Band spectra contain information about molecules.

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ν1 is the frequency of the series limit of the Lyman series, ν2 is the frequency of the first line of the Lyman series and ν3 is the frequency of the series limit of the Balmer series. Then,
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In the following transitions of the hydrogen atom, the one which gives the absorption line of highest frequency is
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The shortest wavelength of the Brackett series of a hydrogen like atom (Atomic number =Z ) is the same as the shortest wavelength of the Balmer series of hydrogen atom. The value of Z is
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Hydrogen (1H1), Deuterium (1H2), singly ionised Helium (2He4)+ and doubly ionised lithium (3Li6)++ all have one electron around the nucleus. Consider an electron transition from n = 2 to n = 1. If the wave lengths of emitted radiation are λ 1 λ 2 λ 3  and λ 4  respectively then approximately which one of the following is correct ?